Program to implement Even Parity in C.

Here is the Code..

#include<stdio.h>

int main()

{

long n;

int a[8],i,c,p;

c=0;

printf("\nEnter a 7 digit binary number");

scanf("%ld",&n);

for(i=6;i>=0;i--)

{

p=n%10;

a[i]=p;

n=n/10;

}

for(i=0;i<7;i++)

{

if(a[i]==1)

c++;

}

if(c%2==0)

{

a[7]=0;

printf("\n EVEN PARITY DETECTED !!! \n\n No need to convert :-) ");

}

else

{

printf("\n ODD PARITY DETECTED !!! ");

a[7]=1;

}

printf("\n New number after adding parity bit is -- ");

for(i=0;i<8;i++)

printf("%d",a[i]);

return 1;

}

For turbo C users.

#include<stdio.h>

#include<conio.h>

void main()

{

long n;

int a[8],i,c,p;

clrscr();

c=0;

printf("\nEnter a 7 digit binary number");

scanf("%ld",&n);

for(i=6;i>=0;i--)

{

p=n%10;

a[i]=p;

n=n/10;

}

for(i=0;i<7;i++)

{

if(a[i]==1)

c++;

}

if(c%2==0)

{

a[7]=0;

printf("\n EVEN PARITY DETECTED !!! \n\n No need to convert :-) ");

}

else

{

printf("\n ODD PARITY DETECTED !!! ");

a[7]=1;

}

printf("\n New number after adding parity bit is -- ");

for(i=0;i<8;i++)

printf("%d",a[i]);

getch();

}